3.33 \(\int \frac {(a+b \sec (e+f x))^2}{(c+d x)^2} \, dx\)

Optimal. Leaf size=23 \[ \text {Int}\left (\frac {(a+b \sec (e+f x))^2}{(c+d x)^2},x\right ) \]

[Out]

Unintegrable((a+b*sec(f*x+e))^2/(d*x+c)^2,x)

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Rubi [A]  time = 0.05, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {(a+b \sec (e+f x))^2}{(c+d x)^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[(a + b*Sec[e + f*x])^2/(c + d*x)^2,x]

[Out]

Defer[Int][(a + b*Sec[e + f*x])^2/(c + d*x)^2, x]

Rubi steps

\begin {align*} \int \frac {(a+b \sec (e+f x))^2}{(c+d x)^2} \, dx &=\int \frac {(a+b \sec (e+f x))^2}{(c+d x)^2} \, dx\\ \end {align*}

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Mathematica [A]  time = 32.07, size = 0, normalized size = 0.00 \[ \int \frac {(a+b \sec (e+f x))^2}{(c+d x)^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[(a + b*Sec[e + f*x])^2/(c + d*x)^2,x]

[Out]

Integrate[(a + b*Sec[e + f*x])^2/(c + d*x)^2, x]

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fricas [A]  time = 0.73, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{2} \sec \left (f x + e\right )^{2} + 2 \, a b \sec \left (f x + e\right ) + a^{2}}{d^{2} x^{2} + 2 \, c d x + c^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sec(f*x+e))^2/(d*x+c)^2,x, algorithm="fricas")

[Out]

integral((b^2*sec(f*x + e)^2 + 2*a*b*sec(f*x + e) + a^2)/(d^2*x^2 + 2*c*d*x + c^2), x)

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sec(f*x+e))^2/(d*x+c)^2,x, algorithm="giac")

[Out]

Timed out

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maple [A]  time = 5.03, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +b \sec \left (f x +e \right )\right )^{2}}{\left (d x +c \right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*sec(f*x+e))^2/(d*x+c)^2,x)

[Out]

int((a+b*sec(f*x+e))^2/(d*x+c)^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {a^{2} d f x + a^{2} c f - 2 \, b^{2} d \sin \left (2 \, f x + 2 \, e\right ) + {\left (a^{2} d f x + a^{2} c f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} + {\left (a^{2} d f x + a^{2} c f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \, {\left (a^{2} d f x + a^{2} c f\right )} \cos \left (2 \, f x + 2 \, e\right ) - 4 \, {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f + {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} + {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \, {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )\right )} \int \frac {{\left (a b d f x + a b c f\right )} \cos \left (2 \, f x + 2 \, e\right ) \cos \left (f x + e\right ) + {\left (a b d f x + a b c f\right )} \cos \left (f x + e\right ) + {\left (b^{2} d + {\left (a b d f x + a b c f\right )} \sin \left (f x + e\right )\right )} \sin \left (2 \, f x + 2 \, e\right )}{d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f + {\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} + {\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \, {\left (d^{3} f x^{3} + 3 \, c d^{2} f x^{2} + 3 \, c^{2} d f x + c^{3} f\right )} \cos \left (2 \, f x + 2 \, e\right )}\,{d x}}{d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f + {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )^{2} + {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \sin \left (2 \, f x + 2 \, e\right )^{2} + 2 \, {\left (d^{3} f x^{2} + 2 \, c d^{2} f x + c^{2} d f\right )} \cos \left (2 \, f x + 2 \, e\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sec(f*x+e))^2/(d*x+c)^2,x, algorithm="maxima")

[Out]

-(a^2*d*f*x + a^2*c*f - 2*b^2*d*sin(2*f*x + 2*e) + (a^2*d*f*x + a^2*c*f)*cos(2*f*x + 2*e)^2 + (a^2*d*f*x + a^2
*c*f)*sin(2*f*x + 2*e)^2 + 2*(a^2*d*f*x + a^2*c*f)*cos(2*f*x + 2*e) - (d^3*f*x^2 + 2*c*d^2*f*x + c^2*d*f + (d^
3*f*x^2 + 2*c*d^2*f*x + c^2*d*f)*cos(2*f*x + 2*e)^2 + (d^3*f*x^2 + 2*c*d^2*f*x + c^2*d*f)*sin(2*f*x + 2*e)^2 +
2*(d^3*f*x^2 + 2*c*d^2*f*x + c^2*d*f)*cos(2*f*x + 2*e))*integrate(4*((a*b*d*f*x + a*b*c*f)*cos(2*f*x + 2*e)*c
os(f*x + e) + (a*b*d*f*x + a*b*c*f)*cos(f*x + e) + (b^2*d + (a*b*d*f*x + a*b*c*f)*sin(f*x + e))*sin(2*f*x + 2*
e))/(d^3*f*x^3 + 3*c*d^2*f*x^2 + 3*c^2*d*f*x + c^3*f + (d^3*f*x^3 + 3*c*d^2*f*x^2 + 3*c^2*d*f*x + c^3*f)*cos(2
*f*x + 2*e)^2 + (d^3*f*x^3 + 3*c*d^2*f*x^2 + 3*c^2*d*f*x + c^3*f)*sin(2*f*x + 2*e)^2 + 2*(d^3*f*x^3 + 3*c*d^2*
f*x^2 + 3*c^2*d*f*x + c^3*f)*cos(2*f*x + 2*e)), x))/(d^3*f*x^2 + 2*c*d^2*f*x + c^2*d*f + (d^3*f*x^2 + 2*c*d^2*
f*x + c^2*d*f)*cos(2*f*x + 2*e)^2 + (d^3*f*x^2 + 2*c*d^2*f*x + c^2*d*f)*sin(2*f*x + 2*e)^2 + 2*(d^3*f*x^2 + 2*
c*d^2*f*x + c^2*d*f)*cos(2*f*x + 2*e))

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mupad [A]  time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {{\left (a+\frac {b}{\cos \left (e+f\,x\right )}\right )}^2}{{\left (c+d\,x\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b/cos(e + f*x))^2/(c + d*x)^2,x)

[Out]

int((a + b/cos(e + f*x))^2/(c + d*x)^2, x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \sec {\left (e + f x \right )}\right )^{2}}{\left (c + d x\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*sec(f*x+e))**2/(d*x+c)**2,x)

[Out]

Integral((a + b*sec(e + f*x))**2/(c + d*x)**2, x)

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